Commit dc650409 authored by Michael Wimmer's avatar Michael Wimmer

fix math issue

parent d0a2c689
Pipeline #20835 passed with stages
in 51 seconds
......@@ -132,8 +132,10 @@ understood: the area swept by an angle difference $d\varphi$
We find:
$$ \int_0^{2\pi} d\varphi \int_0^r_0 r dr = \\
2\pi \int_0^r_0 r dr = 2 \pi \frac{1}{2} r_0^2 = \pi r_0^2$$
\int_0^{2\pi} d\varphi \int_0^r_0 r dr = \\
2\pi \int_0^r_0 r dr = 2 \pi \frac{1}{2} r_0^2 = \pi r_0^2,
which is indeed the area of a circle with radius 0.
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