diff --git a/src/5_atoms_and_lcao_solutions.md b/src/5_atoms_and_lcao_solutions.md
index 1838bff34d9951a3c64aa545fa7310b5683bef9f..063a1ce4479b395081a506484456b982f756dcb4 100644
--- a/src/5_atoms_and_lcao_solutions.md
+++ b/src/5_atoms_and_lcao_solutions.md
@@ -24,18 +24,13 @@
         &\sqrt{κ}e^{-κ(x-x_1)}, x>x_1
     \end{cases}
 $$
-
-  Where $κ = \sqrt{\frac{-2mE}{ħ^2}} = \frac{mV_0}{ħ^2}$.
-
-  The energy is given by $ϵ_1 = ϵ_2 = -\frac{mV_0^2}{2ħ^2}$
-
-  The wave function of a single delta peak is given by
-
-  $$
+    Where $κ = \sqrt{\frac{-2mE}{ħ^2}} = \frac{mV_0}{ħ^2}$.
+    The energy is given by $ϵ_1 = ϵ_2 = -\frac{mV_0^2}{2ħ^2}$
+    The wave function of a single delta peak is given by
+    $$
       \psi_1(x) = \frac{\sqrt{mV_0}}{ħ}e^{-\frac{mV_0}{ħ^2}|x-x_1|}
-  $$
-
-  $\psi_2(x)$ can be found by replacing $x_1$ by $x_2$
+    $$
+    $\psi_2(x)$ can be found by replacing $x_1$ by $x_2$
 
 2. $$
     H = -\frac{mV_0^2}{ħ^2}\begin{pmatrix}
@@ -49,7 +44,6 @@ $$
 3. $$
     ϵ_{\pm} = \beta(1/2+\exp(-2\alpha) \pm \exp(-\alpha))
    $$
-
    Where $\beta = -\frac{mV_0^2}{ħ^2}$ and $α = \frac{mV_0}{ħ^2}|x_2-x_1|$
 
 ### Question 3