From 6841b2d0ce06be3dc903b33eb36f45ac1251be50 Mon Sep 17 00:00:00 2001
From: "T. van der Sar" <t.vandersar@tudelft.nl>
Date: Thu, 24 Feb 2022 22:30:05 +0000
Subject: [PATCH] Update 5_atoms_and_lcao_solutions.md - and more

---
 docs/5_atoms_and_lcao_solutions.md | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/docs/5_atoms_and_lcao_solutions.md b/docs/5_atoms_and_lcao_solutions.md
index 6cd93be3..e24b4395 100644
--- a/docs/5_atoms_and_lcao_solutions.md
+++ b/docs/5_atoms_and_lcao_solutions.md
@@ -114,5 +114,5 @@ $$
 #### Question 4.
 We find the polarization using 
 $$
-P=2e\langle\psi|\hat{x}|\psi\rangle = 2e\left(\phi_1^2\langle 1|\hat{x}| 1 \rangle + \phi_1^2\langle 2|\hat{x}| 2 \rangle \right) = ed(\phi_2^2-\phi_1^2) =ed\frac{\eta}{1-\eta}
+P=2e\langle\psi|\hat{x}|\psi\rangle = 2e\left(\phi_1^2\langle 1|\hat{x}| 1 \rangle + \phi_2^2\langle 2|\hat{x}| 2 \rangle \right) = ed(\phi_2^2-\phi_1^2) =ed\frac{\eta}{1-\eta}
 $$
-- 
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