From e6c970126f4e819e4a3eb717a86ba9fb523d20bf Mon Sep 17 00:00:00 2001
From: Anton Akhmerov <anton.akhmerov@gmail.com>
Date: Wed, 24 Apr 2019 06:58:52 +0000
Subject: [PATCH] typo fix; closes #56
---
src/1_einstein_model.md | 2 +-
1 file changed, 1 insertion(+), 1 deletion(-)
diff --git a/src/1_einstein_model.md b/src/1_einstein_model.md
index 40729e56..d6b2c5db 100644
--- a/src/1_einstein_model.md
+++ b/src/1_einstein_model.md
@@ -257,7 +257,7 @@ C = \frac{\partial\bar{\varepsilon}}{\partial T}
$$
There is still one step to do, rewriting this equation more elegantly:
$$
-C = k_b \left(\frac{T_E}{T}\right)^2\frac{e^{T_E/T}}{(e^{E_T/T} - 1)^2)},
+C = k_b \left(\frac{T_E}{T}\right)^2\frac{e^{T_E/T}}{(e^{T_E/T} - 1)^2)},
$$
where we introduce the *Einstein temperature* $T_E \equiv \hbar \omega / k_B$.
This is a characteristic temperature when the thermal excitations "freeze out" in the harmonic oscillator.
--
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