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Commit 035471a7 authored by Sathish Kumar RK's avatar Sathish Kumar RK
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fix +1 in the fermi function - exercise 3.1

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......@@ -86,7 +86,7 @@ Total energy: $E = \int_{0}^{\infty}g(E)f(E)EdE $
1.
$$
E = \int_{0}^{\infty}\epsilon g(\epsilon)f(\epsilon)d\epsilon = 2.10^{10}\int_{0}^{\infty}\frac{\epsilon^{\frac{3}{2}}}{e^\frac{\epsilon-5.2}{k_BT}}d\epsilon
E = \int_{0}^{\infty}\epsilon g(\epsilon)f(\epsilon)d\epsilon = 2.10^{10}\int_{0}^{\infty}\frac{\epsilon^{\frac{3}{2}}}{e^\frac{\epsilon-5.2}{k_BT}+1}d\epsilon
$$
2.
......
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