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Commit 16951698 authored by Lars kleyn Winkel's avatar Lars kleyn Winkel
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Update src/7_tight_binding_model_sol.md

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......@@ -65,7 +65,7 @@ Hint: The group velocity is given as $v = \frac{d\omega}{dk}$, draw a coordinate
### Subquestion 1
For the energy we have: $$U = \int \hbar \omega g(\omega) (n(\omega,T) + \frac{1}{2})d\omega$$ with $g(\omega)$ as in Exercise 1 subquestion 2 and $n(\omega,T) = \frac{1}{e^{\frac{\hbar\omega}{k_BT}}-1}$.
For the energy we have: $$U = \int \hbar \omega g(\omega) (n(\omega,T) + \frac{1}{2})d\omega$$ with $g(\omega)$ as in Exercise 1 subquestion 2 and $n(\omega,T) = \frac{1}{e^{\hbar\omega/k_BT}-1}$.
### Subquestion 2
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