To calculate $W=\langle k | V |k' \rangle$, we first express the lattice potential, which is periodic as $V(x)=V(x+a)$, as a Fourier series
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@@ -126,9 +126,9 @@ V_n = \frac{1}{a}\int_0^a e^{- i n 2\pi x /a} V(x) dx
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We now calculate the matrix element that couples our basis states $|k\rangle$ and $k'\rangle = |k-2\pi/a '\rangle$
$$W = \langle k | V | k' \rangle = \frac{1}{a}\int_0^{a} dx \left[e^{i k x}\right]^* V(x) \left[e^{-i k'x}\right] = \frac{1}{a}\int_0^a e^{-2\pi i x /a} V(x) dx = V_1$$
$$W = \langle k | V | k' \rangle = \frac{1}{a}\int_0^{a} e^{i k x} V(x) e^{-i k'x} dx = \frac{1}{a}\int_0^a e^{-i 2\pi x /a} V(x) dx = V_1$$
where we have used that $k-k'=2\pi/a$ for the first crossing. We see that the first component of the Fourier-series representation of $V(x)$ determines the strength of the coupling between the two states near the first crossing.
where we have used that $k'-k=2\pi/a$ because we are analyzing the first crossing. We see that the first component of the Fourier-series representation of $V(x)$ determines the strength of the coupling between the two states near the first crossing.