Update 5_atoms_and_lcao_solutions.md - typo

docs/5_atoms_and_lcao_solutions.md

@@ -99,15 +99,15 @@ $$
 $$
 From this we find 
 $$
-beta = -\frac{E_\pm- E_0 + \gamma}{t}\alpha = -\frac{\pm\sqrt{t^2+\gamma^2}}{t}
+\beta = -\frac{E_\pm- E_0 + \gamma}{t}\alpha = -\frac{\pm\sqrt{t^2+\gamma^2}}{t}\alpha 
 $$
 Then, using the normalization condition $\alpha^2+\beta^2$=1, we find the normalized eigenfunction.
 
-The ground state wave function is:
-$$
-    |\psi⟩ &= \frac{\gamma+\sqrt{t^2+\gamma^2}}{\sqrt{(\gamma+\sqrt{\gamma^2+t^2})^2+t^2}}|1⟩+\frac{t}{\sqrt{(\gamma+\sqrt{\gamma^2+t^2})^2+t^2}}|2⟩
-    \end{split}
-$$
+%The ground state wave function is:
+%$$
+%    |\psi⟩ &= \frac{\gamma+\sqrt{t^2+\gamma^2}}{\sqrt{(\gamma+\sqrt{\gamma^2+t^2})^2+t^2}}|1⟩+\frac{t}{\sqrt{(\gamma+\sqrt{\gamma^2+t^2})^2+t^2}}|2⟩
+%    \end{split}
+%$$
 
 #### Question 4.