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Commit 684e5892 authored by Adrian Gutierrez Gonzalez's avatar Adrian Gutierrez Gonzalez
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Update 5_atoms_and_lcao_solutions.md

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......@@ -99,7 +99,7 @@ $$
$$
From this we find
$$
\beta = -\frac{E_\pm- E_0 + \gamma}{t}\alpha = -\frac{\pm\sqrt{t^2+\gamma^2}}{t}\alpha
\beta = -\frac{E_\pm- E_0 + \gamma}{t}\alpha = -\frac{\pm\sqrt{t^2+\gamma^2}+\gamma}{t}\alpha
$$
Then, using the normalization condition $\alpha^2+\beta^2$=1, we find the normalized eigenfunction.
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