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Commit 88b54ed6 authored by T. van der Sar's avatar T. van der Sar
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Update 3_drude_model_solutions.md - typo fix

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......@@ -67,22 +67,22 @@ This equation describes a circular motion around the point $x_0=x(0), y_0=y(0)+v
Due to the applied electric field $\bf E$ in the $x$-direction, the equations of motion acquire an extra term:
$$
m v_x' = -e(E_x + v_yB_z)
m v_x' = -e(E_x + v_yB_z).
$$
This leads to the same 2nd-order D.E. for v_x as above. However, for $v_y$ we get
Differentiating w.r.t. time leads to the same 2nd-order D.E. for $v_x$ as above. However, for $v_y$ we get
$$
v_y'' = -\omega_c^2(\frac{E_x}{B_z}+v_y),
$$
which has as solution
$$
v_y(t) = v_0\sin(\omega_t)-\frac{E_x}{B_z}.
v_y(t) = v_0\sin(\omega_c t)-\frac{E_x}{B_z}.
$$
By integrating the expressions for the velocity we find:
$$
(x(t)-x_0)^2 + (y(t) - y_0 + \frac{E}{B}t))^2 = \frac{v_0^2}{\omega_c^2}
(x(t)-x_0)^2 + (y(t) - y_0 + \frac{E_x}{B_z}t))^2 = \frac{v_0^2}{\omega_c^2}.
$$
This represents a [cycloid](https://en.wikipedia.org/wiki/Cycloid#/media/File:Cycloid_f.gif): a circular motion around a point that moves in the $y$-direction with a constant velocity $\frac{E}{B}$.
This represents a [cycloid](https://en.wikipedia.org/wiki/Cycloid#/media/File:Cycloid_f.gif): a circular motion around a point that moves in the $y$-direction with velocity $\frac{E_x}{B_z}$.
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