@@ -359,11 +359,11 @@ It was previously mentioned that $V_0>0$.
Using this, determine which energy corresponds to the bonding energy.
### Exercise 3: Polarization of a hydrogen molecule
### Exercise 3: Polarization of a hydrogen molecule in an electric field
Applying an electric field can induce an electric dipole moment in a molecule, yielding a 'polarized' molecule. The reason is that the electric field redistributes the charge over the molecule by exerting a force on its charged constituents. Here, we analyze the electric-field-induced dipole moment of a molecule using the LCAO model.
Consider a hydrogen molecule as a one-dimensional system with two identical nuclei at $x=-d/2$ and $x=+d/2$, so that the center of the molecule is at $x=0$.
Each atom contains a single electron with charge $-e$.
The LCAO Hamiltonian of the system is given by
We consider a hydrogen molecule as a one-dimensional system with two identical nuclei at $x=-d/2$ and $x=+d/2$, so that the center of the molecule is at $x=0$.
Each atom contributes a single electron with charge $-e$. The LCAO Hamiltonian of the system is given by
Let us add an electric field $\mathcal{E} \hat{\bf{x}}$ to the system.
Which term needs to be added to the Hamiltonian of each electron?
1.Let us add an electric field $\mathcal{E} \hat{\bf{x}}$ to the system. Which term needs to be added to the Hamiltonian of each electron?
??? hint "The electric potential is given by"
??? hint "The electric potential is given by"
$$
V_{\mathcal{E}}=-\int \mathcal{E} d x
$$
$$
V_{\mathcal{E}}=-\int \mathcal{E} d x
$$
#### Question 2.
Compute the LCAO Hamiltonian of the system in presence of the electric field.
What are the new onsite energies of the two orbitals?
#### Question 3.
Diagonalize the modified LCAO Hamiltonian. Find the ground state wavefunction $ψ$. Note: for simplicity assume that the electric field is small, such that $\gamma \ll t$, with $\gamma = e d \mathcal{E}/2$.
#### Question 4.
Find the polarization $P$ of the molecule in the ground state. Check if your answer makes sense when you set the electric field to zero.
2. Compute the LCAO Hamiltonian of the system in presence of the electric field. What are the new onsite energies of the two orbitals?
3. Diagonalize the modified LCAO Hamiltonian. Find the ground state wavefunction $ψ$. Note: for simplicity assume that the electric field is small, such that $\gamma \ll t$, with $\gamma = e d \mathcal{E}/2$.
4. Find the induced dipole moment $p$ of the molecule in the ground state. Check if your answer makes sense when you set the electric field to zero.
??? hint "Reminder: polarization"
The polarization $P$ of a molecule with $n\leq 2$ electrons at its ground state $|ψ⟩$ is:
??? hint "Reminder: dipole moment"
The dipole moment $p$ of a molecule with $n\leq 2$ electrons in its orbital ground state $|ψ⟩$ is:
$$
P = n e ⟨ψ|x|ψ⟩.
p = n e ⟨ψ|x|ψ⟩.
$$
Use that ground state you found in 3.2 is a linear superposition of two orthogonal orbitals centered at $-d/2$ and $+d/2$.