Updated question Q2 2 and 3

src/5_atoms_and_lcao_solutions.md

@@ -39,18 +39,18 @@ $$
 
 2. $$
     H = -\frac{mV_0^2}{ħ^2}\begin{pmatrix}
-        1/2+\exp(-\frac{mV_0}{ħ^2}(x_2-x_1)) &
-        \exp(\frac{mV_0}{ħ^2}(x_2-x_1))\\
+        1/2+\exp(-\frac{2mV_0}{ħ^2}(x_2-x_1)) &
+        \exp(-\frac{mV_0}{ħ^2}(x_2-x_1))\\
         \exp(-\frac{mV_0}{ħ^2}(x_2-x_1)) &
-        1/2+\exp(+\frac{mV_0}{ħ^2}(x_2-x_1))
+        1/2+\exp(-\frac{2mV_0}{ħ^2}(x_2-x_1))
     \end{pmatrix}
   $$
 
 3. $$
-    ϵ_{\pm} = \beta(3/2+\cosh{2α}+2\cosh{α}\pm \cosh{α})
+    ϵ_{\pm} = \beta(1/2+\exp(-2*\alpha) \pm \exp(-*\alpha))
    $$
 
-   Where $\beta = -\frac{mV_0^2}{ħ^2}$ and $α = \frac{mV_0}{ħ^2}(x_2-x_1)$
+   Where $\beta = -\frac{mV_0^2}{ħ^2}$ and $α = \frac{mV_0}{ħ^2}|x_2-x_1|$
 
 ### Question 3