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Commit ae3e084a authored by Sathish Kumar RK's avatar Sathish Kumar RK
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update solution 2.2

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......@@ -39,10 +39,20 @@ Distance between nearest k-points is $\frac{2\pi}{L}$ and their density across n
2.
$$
g(k)dk = \left(\frac{L}{2\pi}\right)^n\int_k d\bf k
g_{1D}(k)dk = \left(\frac{L}{2\pi}\right) 2 .dk
$$
Check how to convert volume to surface intergral and surface to line integral.
Factor 2 is due to positive and negative k-points having equal energy.
$$
g_{2D}(k)dk = \left(\frac{L}{2\pi}\right)^2 2\pi k . dk
$$
$$
g_{3D}(k)dk = \left(\frac{L}{2\pi}\right)^3 4\pi k^2 . dk
$$
$4\pi k^2$ is the volume of spherical shell enclosed between k and k + dk.
3, 4.
......@@ -190,3 +200,4 @@ $$
$$
C_v(T) = \frac{\partial E}{\partial T} = \frac{3Ak_B^2T^2}{\pi c^2}
$$
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