Since there is only 1 atom in the basis, there are no missing peaks due to a structure factor. We will get diffraction peaks at angles given by Bragg's law $\sin2\theta = \lambda/d_{hkl} = \lambda |\mathbf{G_{hkl}}|/2\pi$. We see that the shortest reciprocal lattice vector gives the smallest angle. Therefore, as a function of increasing $\theta$, we will see peaks at $(hkl)= (100) \quad (010) \quad (110) \quad (200), (020)$, where we took into account that $|\mathbf{b_1}|<|\mathbf{b_2}|$.
Since there is only 1 atom in the basis, there are no missing peaks due to a structure factor. We will get diffraction peaks at angles given by Bragg's law $\sin2\theta = \lambda/d_{hkl} = \lambda |\mathbf{G_{hkl}}|/2\pi$. We see that the shortest reciprocal lattice vector gives the smallest angle. Therefore, as a function of increasing $\theta$, we will see peaks at $(hkl)= (10) \quad (01) \quad (11) \quad (20) \quad (21) \quad (02)$, where we took into account that $|\mathbf{b_1}|<|\mathbf{b_2}|$.
## Exercise 4: Analyzing a 3D power diffraction spectrum