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DifferentialEquationsLecture2

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@@ -264,5 +264,78 @@ For the Schr\"{o}dinger equation, we could supply the initial conditions
$$\psi(x,0)= \psi_{0}(x) \ & \ \psi(0,t) = \psi{t, L} = 0.$$
This particular set of boundary conditions corresponds to a particle in a box,
a basic situation which comes up often in quantum physics.
a situation which is used as the base model for many derivations in quantum
physics.
Another example of a partial differential equation common in physics is the
Laplace equation
$$\frac{\partial^2 \phi(x,y)}{\partial x^2}+\frac{\partial^2 \phi(x,y)}{\partial y^2}=0.$$
In quantum physics Laplace's equation is important for the study of the hydrogen
atom. In three dimensions and using spherical coordinates, the solutions to
Laplace's equation are special functions called spherical harmonics. In the
context of the hydrogen atom, these functions describe the wave function of the
system and a unique spherical harmonic function corresponds to each distinct set
of quantum numbers.
In the study of PDEs there is not a comprehensive overall treatment to the same
extent as there is for ODEs. There are several techniques which can be applied
to solving these equations, but the choice of technique must be tailored to the
equation at hand. Hence we focus on some specific examples that are common in
physics.
## Separation of variables ##
Let us focus on the one dimensional Schr\"{o}dinger equation of a free particle
$$i \hbar \frac{\partial \psi(x,t)}{\partial t} = - \frac{\hbar^2}{2m} \frac{\partial^2 \psi(x,t)}{\partial x^2}. $$
To attempt a solution, we will make a *separation ansatz*,
$$\psi(x,t)=\phi(x) f(t).$$
!!! info "Separation ansatz"
The separation ansatz is a restrictive ansatz, not a fully general one. In
general, for such a treatment to be valid an equation and the boundary
conditions given with it have to fulfill certain properties. In this course
however you will only be asked to use this technique when it is suitable.
Substituting the separation ansatz into the PDE,
$$i \hbar \frac{\partial \phi(x)f(t)}{\partial t} = - \frac{\hbar^2}{2m} \frac{\partial^2 \phi(x)f(t)}{\partial x^2} $$
$$i \hbar \dot{f}(t) \phi(x) = - \frac{\hbar^2}{2m} \phi''(x)f(t). $$
Notice that in the above equation the derivatives on $f$ and $\phi$ can each be
written as ordinary derivatives, $\dot{f}=\frac{df(t)}{dt}$,
$\phi''(x)=\frac{d^2 \phi}{dx^2}$. This is so because each is only a function of
one variable.
Next, divide both sides of the equation through by $\psi(x,t)=\phi(x) f(t)$,
$$i \hbar \frac{\dot{f}(t)}{f(t)} = - \frac{\hbar^2}{2m} \frac{\phi''(x)}{\phi(x)} = constant := \lambda. $$
In the previous line we concluded that each part of the equation must be equal
to a constant, which we defined as $\lambda$. This follows because the left hand
side of the equation only has a dependence on the spatial coordinate $x$, whereas
the right hand side only has dependence on the time coordinate $t$. If we have
two functions $a(x)$ and $b(t)$ such that
$a(x)=b(t) \ \forall x, \ t \ \epsilon \mathbb{R}$, then $a(x)=b(t)=const$.
The constant we defined, $lambda$, is called a *separation constant*. With it, we
can break the spatial and time dependent parts of the equation into two separate
equations,
$$i \hbar \dot{f}(t) = \lambda f(t)$$
$$-\frac{\hbar^2}{2m} \phi''(x) = \lambda \phi(x) .$$
To summarize, this process has broken one partial differential equation into two
ordinary differential equations of different variables. In order to do this, we
needed to introduce a separation constant, which remains to be determined.
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