Update 5_atoms_and_lcao_solutions.md

docs/5_atoms_and_lcao_solutions.md

@@ -99,7 +99,7 @@ $$
 $$
 From this we find 
 $$
-\beta = -\frac{E_\pm- E_0 + \gamma}{t}\alpha = -\frac{\pm\sqrt{t^2+\gamma^2}+\gamma}{t}\alpha 
+\beta = -\frac{E_\pm- E_0 + \gamma}{t}\alpha = -\frac{\pm\sqrt{t^2+ \gamma^2} + \gamma }{t}\alpha 
 $$
 Then, using the normalization condition $\alpha^2+\beta^2$=1, we find the normalized eigenfunction.