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Merged Kostas Vilkelis requested to merge lecture_13 into master
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@@ -155,13 +155,13 @@ Therefore we can approximate the dispersion relation of both bands as parabolic.
Or in other words
$$E_e = E_c + \frac{\hbar^2k^2}{2m_e},$$
$$E_h = E_{v,h} + \frac{\hbar^2k^2}{2m_h} = -E_{v} + \frac{\hbar^2k^2}{2m_h}$$,
$$E_h = E_{v,h} + \frac{\hbar^2k^2}{2m_h} = -E_{v} + \frac{\hbar^2k^2}{2m_h},$$
with the corresponding density of states
$$ E_h = -E_V + {p^2}/{2m_h}$$
$$ g(E) = (2m_e)^{3/2}\sqrt{E-E_c}/2\pi^2\hbar^3$$
$$ g(E_h) = (2m_h)^{3/2}\sqrt{E_h+E_v}/2\pi^2\hbar^3$$.
$$ g(E_h) = (2m_h)^{3/2}\sqrt{E_h+E_v}/2\pi^2\hbar^3.$$
Here $E_c$ is the energy of an electron at the bottom of the conduction band and $E_v$ is the energy of an electron at the top of the valence band.
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