\hspace fix

src/3_vector_spaces.md

@@ -90,16 +90,17 @@ You might be already familiar with the concept of performing a number of various
 !!! info "Scalar multiplication" 
     I can multiply a vector by a scalar number (either real or complex) to produce another vector, $$\vec{c} = \lambda \vec{a}.$$ 
     Addition and scalar multiplication of vectors are both *associative* and *distributive*, so the following relations hold
-    $$1. \vspace{5pt} (\lambda \mu) \vec{a} = \lambda (\mu \vec{a}) = \mu (\lambda \vec{a})$$
-    $$2. \vspace{5pt} \lambda (\vec{a} + \vec{b}) = \lambda \vec{a} + \lambda \vec{b}$$
-    $$3. \vspace{5pt} (\lambda + \mu)\vec{a} = \lambda \vec{a} +\mu \vec{a}$$
+    $$1. \hspace{5pt} (\lambda \mu) \vec{a} = \lambda (\mu \vec{a}) = \mu (\lambda \vec{a})$$
+    $$2. \hspace{5pt} \lambda (\vec{a} + \vec{b}) = \lambda \vec{a} + \lambda \vec{b}$$
+    $$3. \hspace{5pt} (\lambda + \mu)\vec{a} = \lambda \vec{a} +\mu \vec{a}$$
+ 
+### Vector products
 
-!!! info "Vector product" 
-    In addition to multiplying a vector by a scalar, as mentioned above, one can also multiply two vectors among them. 
-    There are two types of vector productions, one where the end result is a scalar (so just a number) and the other where the end result   is another vectors. 
+In addition to multiplying a vector by a scalar, as mentioned above, one can also multiply two vectors among them. 
+There are two types of vector productions, one where the end result is a scalar (so just a number) and the other where the end result   is another vectors. 
 
-!!! info "The scalar production of vectors" 
-    The **scalar production of vectors is given by $$ \vec{a}\cdot \vec{b} = a_1b_1 + a_2b_2 + \ldots + a_nb_n \, .$$
+!!! info "Scalar product of vectors" 
+    The scalar product of vectors is given by $$ \vec{a}\cdot \vec{b} = a_1b_1 + a_2b_2 + \ldots + a_nb_n \, .$$
     Note that since the scalar product is just a number, its value will not depend on the specific
     basis in which we express the vectors: the scalar product is said to be *basis-independent*. The scalar product is also found via 
     $$\vec{a} \cdot \vec{b} = |\vec{a}||\vec{b}| \cos \theta$$ with $\theta$ the angle between the vectors.